7 × (5 - 2) + 4 = 7 × 3 + 4 = 21 + 4 = 25

16 ÷ 4 × (5 - 3) = 4 × 2 = 8

(8 + 2) × 3 - 4 ÷ 2 = 10 × 3 - 2 = 30 - 2 = 28

(9 - 5) × (6 ÷ 3) + 4 = 4 × 2 + 4 = 8 + 4 = 12

21 ÷ 7 × (3 + 2) = 3 × 5 = 15

(7 - 3) × (12 ÷ 4) + 2 = 4 × 3 + 2 = 12 + 2 = 14

3 + (12 ÷ 4 × 2) = 3 + 3 × 2 = 3 + 6 = 9

Question: 3 × 3 − 3 ÷ 3 + 3 =11​

Let's solve this step by step, remembering the order of operations (PEMDAS/BODMAS):

1. Multiplication: $3\times 3=9$
2. Division: $3÷3=1$

Now the expression looks like this: $9-1+3$

3. Subtraction: $9-1=8$
4. Addition: $8+3=11$

So, 3 × 3 − 3 ÷ 3 + 3 =11​.